The diagonal of a rectangle is 8m longer than its shorter side. If the area of the rectangle is 60 square meters. find its dimensions.

Answer 1

length = a
width = b
a b = 60
so b = 60/a
sqrt (a^2 + b^2) = b+8
a^2 + b ^2 = b^2 + 16 b + 64
a^2 - 16 b - 64 = 0
a^2 - 16 (60/a) - 64 = 0
a^3 - 960 - 64 a = 0
a^3 - 64 a - 960 = 0
try a = 11. a = 11 a = 12
if a = 12
1728 - 768 = 960 !!!!
so a = 12
then b = 60/12 = 5