how to find the dimension if the diagonal of the rectangle is 8 meters longer than its shorter side and the area of the rectangle is 60 square meters?

Answer 1

If the dimensions are x and y, then we have

√(x^2+y^2) = x+8
xy = 60

You can grind out the solution, but I think you can recognize which factors of 60 form a convenient right triangle that works, no?

Answer 2

S * L = 60

S² + L² = (S + 8)²

S² + (60 / S)² = (S + 8)²

S² + (3600 / S²) = (S + 8)²

S⁴ + 3600 = S⁴ + 16 S³ + 64 S²

S³ + 4 S² - 225 = 0

S = 5

Answer 3

Steve is referring to the 5-12-13 Pythagorean triple