918/1030 = 89.12%
That means that 10.88% of the berg is showing.
so, 224 = 0.1088v
The density of the ice is 918kgm-3 and that of water is 1030kgm-3. An iceberg floats with a portion of 224 litre outside water. Find the volume of the iceberg.
4 answers
Here,
First of all we will convert 224 litres into m³ as 1l = 1000m³
= 224l = 224/1000 m³
Now ,
Density of iceberg = DVG
density of water = dvg
DVG = dvg
918 × V= 1030×224/1000....(1)
V= volume of iceberg
From ...(1)
0.25 m³....@nswer
First of all we will convert 224 litres into m³ as 1l = 1000m³
= 224l = 224/1000 m³
Now ,
Density of iceberg = DVG
density of water = dvg
DVG = dvg
918 × V= 1030×224/1000....(1)
V= volume of iceberg
From ...(1)
0.25 m³....@nswer
Vb = (918/1030)*V = V-224. = Vol. below surface.
V = 2036 Liters.
V = 2036 Liters.
Not sure about answer. But I think it is wrong answer.........