When an iceberg floats in the ocean, what fraction of it is visible?( The relative density of ice is 0.92, and the relative density of sea water is 1.03)

Answer 1

Use Archimedes' Principle.

Let the volume of the iceberg be V. The amount below water (V') must displace a weight of sea water equal to the weight of the iceberg.

seawater density x V' = ice density * V

1.03*V' = 0.92*V

V'/V = fraction below water = 0.89

Fraction above water = 1 - V'/V = 0.11