The density of the dead sea is 1.24x10^3 kg m^-3. A wooden board with an area of 2.5m^2 is dropped in the Dead Sea. Calculate the proportion that would float above the surface.

Question

The density of the dead sea is 1.24x10^3 kg m^-3. A wooden board with an area of 2.5m^2 is dropped in the Dead Sea. Calculate the proportion that would float above the surface.
Density of wood= 800kg m^-3

plumpycat · Answer

Proportion submersed = density of wood/density of Dead Sea = 800/(1.24 *10^3) ~ 0.65 or 65 % So the proportion above the surface would be 1 minus that.