Proportion submersed = density of wood/density of Dead Sea
= 800/(1.24 *10^3)
~ 0.65 or 65 %
So the proportion above the surface would be 1 minus that.
The density of the dead sea is 1.24x10^3 kg m^-3. A wooden board with an area of 2.5m^2 is dropped in the Dead Sea. Calculate the proportion that would float above the surface.
Density of wood= 800kg m^-3
1 answer