Asked by Anonymous
The density of ice is 9.20x10² kg/m³. An ice cube which is 20.0mm high floats in water. What height of the side of the ice cube is above the surface of the water?
Answers
Answered by
bobpursley
what is .92 times 20mm? That is the height below the water surface. Why does that work? Think the submerged height creates a bouyant force due to the displaced volume...Why is 90 percent of icebergs beneith the surface?
Answered by
Henry2
Hb = Di/Dw * H = Height below surface.
Di = 920 kg/m^3.
Dw = 1000 kg/m^3.
H = 20 mm.
Hb = 920/1000 * 20 = 18.4 mm.
20 - 18.4 = 1.6 mm above surface.
P.S. So, as bob said, 92%(18.4mm) is below surface.
Di = 920 kg/m^3.
Dw = 1000 kg/m^3.
H = 20 mm.
Hb = 920/1000 * 20 = 18.4 mm.
20 - 18.4 = 1.6 mm above surface.
P.S. So, as bob said, 92%(18.4mm) is below surface.
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