Question
A cube of side length 11.0 cm and made of unknown material floats at the surface between water and oil. The oil has a density of 810 kg/m^3.
a)If the cube floats so that it is 70% in the water and 30% in the oil, what is the mass of the cube?
b)What is the buoyant force on the cube?
a)If the cube floats so that it is 70% in the water and 30% in the oil, what is the mass of the cube?
b)What is the buoyant force on the cube?
Answers
the volume of the cube is 11^3 cc
the mass of the cube is:
11^3x0.7x1 g/cc + 11^3x0.3x0.81 g/cc
bouyant force = mass of cube x g
the mass of the cube is:
11^3x0.7x1 g/cc + 11^3x0.3x0.81 g/cc
bouyant force = mass of cube x g
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