The density of a substance at 100 degrees centigrade is 1.22 g/(cm^3) and at 140 degrees centigrade is 0.95 g/(cm^3). Estimate the density at 115 degrees centigrade using linear interpolation. Observe significant digits.

Answer 1

D1 = 1.22g/cm^3, T1 = 100oC.
D2 = 0.95g/cm^3, T2 = 140oC.
D3 = density @ 115oC.

T.C. = (D2- D1)/(T2 - T1) = (0.95-1.22)/(140-100) = -0.00675/oC. = Temp.
coefficient.

D3 = D1 + (T.C.)*(T3-T1)D1 = 1.22 + (-0.00675)*(115-100) = 1.22 - 0.10125 = 1.11875 g/cm^3.