If you need to show the work by hand, you can develop the regression equation in the following format:
predicted y = a + bx
...where a represents the y-intercept and b the slope.
Note: x = height; y = time
To get to that point, here are some formulas to calculate along the way.
To find a:
a = (Ey/n) - b(Ex/n)
Note: E means to add up or to find the total.
To find b:
b = SSxy/SSxx
To find SSxy:
SSxy = Exy - [(Ex)(Ey)]/n
To find SSxx:
SSxx = Ex^2 - [(Ex)(Ex)]/n
Once you have the formula, you can determine the best predicted time using 149 for feet.
I hope this will help get you started.
The data show the time intervals is after
an eruption(to the next eruption) of a certain geyser. Find the regression equation, letting the first variable be the independent (r) variable. Find the best predicted time of the interval after an eruption that the current eruption has a height of 149 feet. Use a significance
level of 0.05 Height(ft) interval after(min) What is the regression equation. round to two decimal places
as needed.
Height(ft) 108 124 108 152 109 138 137 103
interval after (min) 77 73 81 87 69 91 90 68
2 answers
sfds