To find the probability that the number of units produced per day is greater than 173, we first need to standardize the value and then use the standard normal distribution table.
Z = (X - μ) / σ
Z = (173 - 165) / √25
Z = 8 / 5
Z = 1.6
Now, we look up the Z value of 1.6 in the standard normal distribution table. The probability corresponding to a Z value of 1.6 is 0.9452.
Since we are looking for the probability that the number of units produced per day is greater than 173, we subtract the obtained probability from 1:
P(Z > 1.6) = 1 - 0.9452 = 0.0548
Therefore, the probability that the number of units produced per day is greater than 173 is 0.0548.
The daily output of an assembly line is normally distributed with the mean of 165 and the variance of 25 units. Find the probability that the number of units produced per day is greater than 173.
0.7500
0.2266
0.7734
0.5468
0.0548
1 answer