The daily output of an assembly line is normally distributed with the mean of 165 and the variance of 25 units. Find the probability that the number of units produced per day is greater than 173.

Question

0.7500


0.2266


0.7734


0.5468


0.0548

Answer 1

To solve this problem, we need to first calculate the standard deviation since we are given the variance.

Standard Deviation = sqrt(variance) = sqrt(25) = 5

To find the probability that the number of units produced per day is greater than 173, we need to find the z-score for 173 and use the z-table to find the probability.

z-score = (X - mean) / standard deviation = (173 - 165) / 5 = 1.6

Using the z-table, we find that the probability of a z-score of 1.6 or greater is 0.0548.

Therefore, the probability that the number of units produced per day is greater than 173 is 0.0548.