1/6.25 = e^-(125 t)
.16 = e^-(125 t)
ln .16 = -125 t
-1.83 = -125 t
The current i in a certain circuit is given by
i=6.25e^-125t (amperes)
where t is the time in seconds. At what time will the current be 1.00 A?
1 answer