Part 1:
To calculate the weight/volume percent concentration of glucose in the blood, we first convert the given concentration from mg/100mL to g/L:
92 mg/100 mL = 0.92 g/100 mL = 0.92 g/L
Next, we divide the mass of glucose by the volume of blood sample and multiply by 100 to get the weight/volume percent concentration:
Weight/volume percent concentration = (0.92g/100mL) / 1000 (mL/L) x 100 = 0.092% or 0.092 g/L
Therefore, the weight/volume percent concentration of glucose in the blood is 0.092%.
Part 2:
To calculate the molarity of glucose in the blood, we first convert the concentration from mg/100mL to g/L:
0.092 g/L / 180.15 g/mol = 5.1 x 10^-4 mol/L
Therefore, the molarity of glucose in the blood is 5.1 x 10^-4 mol/L or 0.00051 M.
The concentration of glucose (C6H1206) in a sample of blood is 92. mg/ 100. mL The molar mass of glucose is 180.15 g/mol Be sure each of your answer entries has the correct number of significant figures.
Note: Reference the SI prefixes table for additional information.
Part 1 of 2
What is the weight/volume percent concentration of glucose in the blood?
glucose
What is the molarity of glucose in the blood?
1 answer