Convert 5.97 g glucose to mols.
Convert mols Glucose to mols CO2 using the coefficients in the balanced equation.
Convert mols CO2 at STP to volume (22.4 L/mol) CO2 at STP. This is the theoretical yield.
Now use PV = nRT to convert 1.44 L CO2 at the cnoditions listed to mols of CO2, then convert to volume CO2 at STP (again, 22.4 L/mol at STP conditions). This is the actual amount produced.
%yield = [actual yield/theoretical yield]*100 = ??
Post your work if you get stuck.
In alcohol fermentation, yeast converts glucose to ethanol and carbon dioxide
C6H1206 -----> 2C2H5OH + 2CO2
If 5.97 g of clucose are reacted and 1.44 L of CO2 gas are collected at 293 K and .984 atm, what is the percent yield of the reaction?
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38
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