b. 0.0032 M
To solve for the concentration of NaOH, you can use the formula for pH: pH = -log[H+]. Since NaOH is a strong base that dissociates completely in solution, the [OH-] concentration is the same as the [NaOH] concentration.
Given that the pH is 11.8, first calculate the [H+] concentration:
pH = -log[H+]
11.8 = -log[H+]
[H+] = 10^(-11.8) = 6.31 x 10^-12 M
Since [OH-] = [NaOH] = 6.31 x 10^-12 M, which is equivalent to 0.0032 M.
The concentration of a NaOH solution with pH of 11.8 is:
a.0.010 M
b.0.0032 M
c.0.00032 M
d.0.0063 M
1 answer