How many moles oxalic acid do you have? That is M x L = moles.
Using the coefficients in the balanced equation, convert moles oxalic acid to moles NaOH.
Then M NaOH = moles NaOH/dm^3 NaOH
Calculate the concentration of the NaOH solution. If 30,0cm3 of a standard oxalic acid[(COOH)2] solution of concentration 0,5 mol.dm-3,is used to neutralize 25,0 cm3 of a sodium hydroxide (NaOH) solution. The balanced chemical equation for the reation is (COOH)2(aq) + 2NaOH(aq) forms (COONa)2(aq)
2 answers
0,6