a. tan(theta) = Ay/Ax =11 / 11 = 1,
theta = 45deg.
The components of vector A are Ax and Ay (both positive), and the angle that it makes with respect to the positive x axis is θ. Find the angle θ if the components of the displacement vector A are (a) Ax = 11 m and Ay = 11 m, (b) Ax = 19 m and Ay = 11 m, and (c) Ax = 11 m and Ay = 19 m.
4 answers
Ax = 11 + 19 + 11
Ax = 41
Ay = 11 + 11 + 19
Ay = 41
tan(theta) = Ay/Ax
tan(theta) = 41/41
theta = inverse tan x (41/41)
theta = 45 degrees with respect to positive x axis
Ax = 41
Ay = 11 + 11 + 19
Ay = 41
tan(theta) = Ay/Ax
tan(theta) = 41/41
theta = inverse tan x (41/41)
theta = 45 degrees with respect to positive x axis
How did you get theta=45degree
Ax=15m and Ay=15m