20L propane = 20L x (1 mol/22.4L) = about 0.892 mols propane. You get 2220 kJ for 1 mol; therefore, you will get
2220 x (0.892 mol/1 mol) = ? kJ released.
The complete combustion of propane, C3H8(g), is represented by the equation:
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l) ΔH° = -2220 kJ
How much heat is evolved in the complete combustion of 20.0 L C3H8(g) at STP?
2 answers
329
1 answer