To find the volume of oxygen needed for the complete combustion of 3.3 dm³ of propane (C₃H₈), we will use the balanced chemical equation for the combustion of propane:
\[ \text{C}_3\text{H}_8 + 5\text{O}_2 \rightarrow 3\text{CO}_2 + 4\text{H}_2\text{O} \]
From the balanced equation, we can see that 1 volume of propane reacts with 5 volumes of oxygen.
Given that the volume of propane is 3.3 dm³, we will calculate the volume of oxygen required:
\[ \text{Volume of oxygen} = 5 \times \text{Volume of propane} = 5 \times 3.3 , \text{dm}^3 = 16.5 , \text{dm}^3 \]
Thus, the volume of oxygen needed for the complete combustion of 3.3 dm³ of propane is 16.5 dm³ at STP.
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