the combustion of co2 gives -393.5kj/mol calculate the heat of formation of 35.2grams of co2

Answer 1

enthalpy of combustion of CO2=-393.5 kJ/mol

enthalpy of formation of CO2 = -enthalpy of combustion of CO2 = -(-393.5 kJ/mol) = 393.5 kJ/mol

number of moles of CO2 = mass CO2/molecular mass of CO2 = 35.2 g/ (12.01+16.0x2)g/mol =0.800 mol

1 mol of CO2 formed using 393.5 kJ
0.800 mol of CO2 formed using 0.8x393.5 kJ = 314.8 kJ

Answer 2

How does one combust CO2? Burn it with oxygen? fat chance.

Answer 3

Thanks this answer is absolutely correct