For a chemistry lab, I have to calculate the heat of combustion of paraffin wax. So how would I do that?
And for the second part of the lab, I have to calculate the heat of fusion of ice from my data. How would I do that?
I'm kind of confused so can I get a bit of guidance.
4 answers
You must have data for both parts but you did't share any of that. We aren't clairvoyant, at least not yet.
Heat of Combustion of paraffin wax
Initial mass of candle 40.3g
Mass of tin calorimeter 41.1g
Mass of half-filled calorimeter with water 220.4g
Initial temp of water 18.8°C
Final temp of water 26.6°C
Final mass of candle 38.2g
Calculate heat of combustion of paraffin wax
Heat of fusion of ice lab
Initial mass of empty cup calorimeter 9.55g
Initial mass of water 200.15g
Initial mass of ice + water 209.7g
Initial temp of water 41.9°C
Initial mass of ice 26.9g
Final mass of cup 9.55g
Final mass of water 227.05g
Final mass of cup + water 236.6g
Final temp of water 26.9°C
Calculate the heat of fusion of ice
Initial mass of candle 40.3g
Mass of tin calorimeter 41.1g
Mass of half-filled calorimeter with water 220.4g
Initial temp of water 18.8°C
Final temp of water 26.6°C
Final mass of candle 38.2g
Calculate heat of combustion of paraffin wax
Heat of fusion of ice lab
Initial mass of empty cup calorimeter 9.55g
Initial mass of water 200.15g
Initial mass of ice + water 209.7g
Initial temp of water 41.9°C
Initial mass of ice 26.9g
Final mass of cup 9.55g
Final mass of water 227.05g
Final mass of cup + water 236.6g
Final temp of water 26.9°C
Calculate the heat of fusion of ice
mass paraffin wax = initial mass candle - final mass candle.
mass H2O = mass calorimeter and H2O - mass tin calorimeter.
q = heat from combustion =
[mass H2O x specific heat H2O x (Tfinal-Tinitial)] + [mass calorimeter x specific heat calorimeter x (Tfinal-Tinitial) = 0 That gives you q for the grams wax combusted. You may want kJ/mol or kJ/gram or whatever. You will need to convert to whatever units needed. I assume the heat capacity of the calorimeter is not given; you will need to look u the specific heat of tin. Since you didn't give details I'm assuming I can guess about how the experiment was conducted.
mass H2O = mass calorimeter and H2O - mass tin calorimeter.
q = heat from combustion =
[mass H2O x specific heat H2O x (Tfinal-Tinitial)] + [mass calorimeter x specific heat calorimeter x (Tfinal-Tinitial) = 0 That gives you q for the grams wax combusted. You may want kJ/mol or kJ/gram or whatever. You will need to convert to whatever units needed. I assume the heat capacity of the calorimeter is not given; you will need to look u the specific heat of tin. Since you didn't give details I'm assuming I can guess about how the experiment was conducted.
Thank you so much but
What about the heat of fusion question?
Heat of fusion of ice lab
Initial mass of empty cup calorimeter 9.55g
Initial mass of water 200.15g
Initial mass of ice + water 209.7g
Initial temp of water 41.9°C
Initial mass of ice 26.9g
Final mass of cup 9.55g
Final mass of water 227.05g
Final mass of cup + water 236.6g
Final temp of water 26.9°C
Calculate the heat of fusion of ice
What about the heat of fusion question?
Heat of fusion of ice lab
Initial mass of empty cup calorimeter 9.55g
Initial mass of water 200.15g
Initial mass of ice + water 209.7g
Initial temp of water 41.9°C
Initial mass of ice 26.9g
Final mass of cup 9.55g
Final mass of water 227.05g
Final mass of cup + water 236.6g
Final temp of water 26.9°C
Calculate the heat of fusion of ice
0 answers