Asked by Ashley
The combined math and verbal scores for students taking a national standardized examination for college admission, is normally distributed with a mean of 620 and a standard deviation of 220. If a college requires a student to be in the top 10 % of students taking this test, what is the minimum score that such a student can obtain and still qualify for admission at the college?
answer:(round to the nearest integer)
answer:(round to the nearest integer)
Answers
Answered by
Reiny
using my favourite normal distribution graphing calculator (same as tables in back of text books)
http://davidmlane.com/hyperstat/z_table.html
click on
"value from an area"
then enter:
area = .9 (to be in top 10%, 90 must be "below" )
mean = 620
SD = 220
click on "below" and recalculate to get 901.98 or 902
http://davidmlane.com/hyperstat/z_table.html
click on
"value from an area"
then enter:
area = .9 (to be in top 10%, 90 must be "below" )
mean = 620
SD = 220
click on "below" and recalculate to get 901.98 or 902
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