The coefficient of static friction between the 3.00 kg crate and the 35.0 degree incline is .300. What minimum force must be applied to the crate from sliding down the incline?

Answer 1

force gravity down plane: 3g*sin35
force friction up plane=mu*3g*cos35
forces up plane=forces down plane
so F+mu*3g*cos35=3g*sin35

so figure and solve for F

Answer 2

Ok I tried an didn't even come close to the right answer.