The chemical reaction for the generation of gas in an automobile safety air bag is 2NaN3(s)→ 2Na(s)+3N2(g)

Question

What volume of gas is produced if there are 130.0 grams of NaN3 used in the
reaction? (The density of nitrogen gas is 0.916 g/L.) Please show your work.

Answer 1

2NaN3 ==> 2Na + 3N2
mols N2 gas = grams/molar mass = x mols N2
Using the coefficients in the balanced equation, convert mols N2 to mols NaN3. That's x mols N2*(2 mols NaN3/3 mols N2) = x mols N2*(2/3) = ? mols NaN3.
Then ? mols NaN3 x molar mass NaN3 = grams NaN3.

Answer 2

i need help

Answer 3

130 gm is 2 mol of NaN3 so we will get 3 mol of N2 gas as output
That corresponds to 84 gms of mass which corresponds to 91.7 L of Nitrogen at some elevated temperature (i.e above STP)