Let's assume that the amount of paper required to wrap a small clothing box is s feet, and the amount of paper required to wrap a large clothing box is l feet.
From the first day of wrapping, we know that:
15s + 36l = 492 (1)
From the second day of wrapping, we know that:
39s + 17l = 360 (2)
To solve this system of equations, we can use the method of substitution.
From equation (2), we can isolate s:
39s = 360 - 17l
s = (360 - 17l)/39
Now we substitute this expression for s in equation (1):
15((360 - 17l)/39) + 36l = 492
Multiplying through by 39 to clear fractions:
15(360 - 17l) + 36(39l) = 492(39)
5400 - 255l + 1404l = 19218
5400 + 1149l = 19218
1149l = 13618
l = 13618/1149
l is approximately 11.8 feet.
Now we substitute this value for l in equation (2):
39s + 17(11.8) = 360
39s + 200.6 = 360
39s = 159.4
s is approximately 4.1 feet.
Therefore, it takes approximately 4.1 feet of paper to wrap each small clothing box, and approximately 11.8 feet of paper to wrap each large clothing box.
The cheerleaders from Danville High School are doing a giftwrapping fundraiser at a clothing store. Yesterday, they wrapped 15 small clothing boxes and 36 large clothing boxes, using a total of 492 feet of wrapping paper. The day before, they wrapped 39 small clothing boxes and 17 large clothing boxes, using a total of 360 feet of gift wrap. How much paper does it take to wrap each size of box?
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