Let x be the number of chocolate bars with almonds sold.
Let y be the number of chocolate bars with peanut butter filling sold.
The total profit from selling chocolate bars with almonds is $1.00x.
The total profit from selling chocolate bars with peanut butter filling is $0.80y.
To earn at least $200, the total profit should be greater than or equal to $200.
Therefore, the inequality to model this situation is:
$1.00x + $0.80y ≥ $200.
To graph this inequality, we first plot the line $1.00x + $0.80y = $200.
To do this, we can solve the equation for y:
$0.80y = $200 - $1.00x
y = ($200 - $1.00x)/$0.80
Next, we find two points that lie on this line. We can choose x-intercept and y-intercept values for convenience.
When x = 0, y = ($200 - $1.00(0))/$0.80 = $200/$0.80 = 250.
So (0, 250) is a point on the line.
When y = 0, x = ($200 - $1.00y)/$1.00 = $200/$1.00 = 200.
So (200, 0) is a point on the line.
Plotting these points and drawing the line that connects them, we get:
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The shaded region above the line represents all the possible solutions.
The cheerleaders at the high school need to earn money to help pay for their uniforms. They plan to have a fundraiser selling two different types of chocolate bars.
They need to earn at least $200.
For every chocolate bar with a peanut butter filling (y) that they sell, they will make a profit of $0.80.
For every chocolate bar with almonds (x) that they sell, they will make a profit of $1.00.
Write an inequality to model this situation and graph the inequality on the grid at the left to show all the possible solutions. Be sure to label your graph.
1 answer
1 answer