To determine which combination Leo can afford with his $15 budget using the expression \(4a + 2b\), let's evaluate each option:
-
1 food item and 5 attractions:
\[ \text{Cost} = 4(1) + 2(5) = 4 + 10 = 14 \] This is within the budget of $15. -
0 food items and 8 attractions:
\[ \text{Cost} = 4(0) + 2(8) = 0 + 16 = 16 \] This exceeds the budget of $15. -
2 food items and 4 attractions:
\[ \text{Cost} = 4(2) + 2(4) = 8 + 8 = 16 \] This also exceeds the budget of $15. -
3 food items and 2 attractions:
\[ \text{Cost} = 4(3) + 2(2) = 12 + 4 = 16 \] This exceeds the budget of $15 as well.
The only combination that Leo can afford is 1 food item and 5 attractions.