A carnival is arriving in the neighborhood.Leo has saved a $15 to spend at the carnival on food and attractions.Food items cost $4 each and attractions cost $2.Each Lea uses the expression 4 a plus 2B.To determine the total cost for a food item and b attractions

Select one of the following combinations of food items and attractions that leo can afford with his fifteen dollar budget

Zero food items and eight attractions two food items and four attractions three food items and two attractions one food item and five attractions

1 answer

To determine which combinations Leo can afford with his $15 budget using the expression \(4a + 2b\), we need to substitute the values of \(a\) (food items) and \(b\) (attractions) for each option provided.

  1. Zero food items and eight attractions:

    • \(a = 0\), \(b = 8\)
    • Cost = \(4(0) + 2(8) = 0 + 16 = 16\)
    • Total: $16 (not affordable)
  2. Two food items and four attractions:

    • \(a = 2\), \(b = 4\)
    • Cost = \(4(2) + 2(4) = 8 + 8 = 16\)
    • Total: $16 (not affordable)
  3. Three food items and two attractions:

    • \(a = 3\), \(b = 2\)
    • Cost = \(4(3) + 2(2) = 12 + 4 = 16\)
    • Total: $16 (not affordable)
  4. One food item and five attractions:

    • \(a = 1\), \(b = 5\)
    • Cost = \(4(1) + 2(5) = 4 + 10 = 14\)
    • Total: $14 (affordable)

The only combination that Leo can afford with his $15 budget is one food item and five attractions.