To calculate the force on the cannonball, we first need to calculate the acceleration of the cannonball in the barrel using the formula:
a = (Vf^2 - Vo^2) / (2 * d)
where:
a = acceleration (30,625 m/s^2)
Vo = initial velocity (0 m/s)
Vf = final velocity (350 m/s)
d = distance (2 m)
Now, we can calculate the force using Newton's second law of motion:
F = m * a
where:
F = force
m = mass (5 kg)
a = acceleration
Plugging in the values, we get:
F = 5 kg * 30,625 m/s^2
F = 153,125 N
Therefore, the force on the cannonball is 153,125 N.
The cannon on a pirate ship shoots with a speed of 350 m/s (the muzzle velocity). The cannon can be adjusted to shoot at any elevation above the horizontal. If the cannon's barrel is 2 m long and the force on the ball is constant, and the acceleration if the ball in m/s^2 inside the barrel is 30,625, and the cannon ball mass is 5 kg, then what is the force on the cannon ball in N?
1 answer
1 answer