Asked by satvik
The cannon on a pirate ships shoots cannon balls with a speed of 350m/s (the muzzle velocity). The cannon can be adjusted to shoot at any elevation above the horizontal.
What is the greatest kinetic energy the cannon ball can have when it hits its target in J? Ignore air resistance and assume the target is at the same height above the ground (or water) as the cannon.
What is the greatest kinetic energy the cannon ball can have when it hits its target in J? Ignore air resistance and assume the target is at the same height above the ground (or water) as the cannon.
Answers
Answered by
Damon
Since the cannon and the target are at the same height there is no change in potential energy between start and finish.
Therefore there is no change in kinetic energy as well between start and finish since the no energy is lost or gained during the flight.
(1/2) m v^2 = (1/2) * 5 * 350^2 = 306250 Joules
Therefore there is no change in kinetic energy as well between start and finish since the no energy is lost or gained during the flight.
(1/2) m v^2 = (1/2) * 5 * 350^2 = 306250 Joules
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