over the snow her speed is
30 mi/hr * 5280 ft/mi * 1 hr/3600 sec = 44 ft/second
for 5 down, 12 horizontal, hypotenuse is 13
so speed down = 44 * 5/13 = 17 ft/s
so I get
11,000 - 17 t
The bottom of a ski slope is 6,500 feet above sea level, the top of the slope is 11,000 feet above sea level, and the slope drops 5 feet vertically for every 12 feet traveled in the horizontal direction. From the top of the slope, Kayla skis at an average speed of 30 miles per hour down the slope. Which of the following functions gives the best estimate for the distance above sea level, d, Kayla is t seconds after she begins her ski run where 6,500 < d < 11,000? [Note: 5,280 feet = 1 mile]
A. d(t) = 11,000 - (572/5)
B. d(t) = 11,000 - 8.8t
C. d(t) = 11,000 - 44t
D. d(t) = 4,500 - 1,200t
2 answers
thank you