Note the correct spelling of celsius.
delta T = Kb*molality
solve for molality
0.15 = 0.512*m and
m = 0.15/0.512
Then substitute molality into the freezing point depression equation.
delta T = Kf*m
delta T = 1.86*(0.15/0.512)
delta T = 0.5449 which rounds to 0.54 to two significant figures.
The boiling point of an aqueous solution is elevated by 0.15 degrees celcius. the change in freezing point of the solution, delta T, is?
a.) -6.32
b.) 0.15
c.) -0.15
d.) 0.54
e.) -0.54
I know the answer is d, i just don't understand how to get it! thanks!
1 answer
1 answer