The body mass index (BMI) of an individual varies directly as the weight of the individual and inversely as the square of the height of the individual. The body mass index for a 132-lb person who is 66 in. tall is 21.3. Determine the BMI for an individual who is 61 in. tall and 158 lb.

1 answer

The body mass index (BMI) can be expressed with the formula:

\[ \text{BMI} = k \cdot \frac{W}{H^2} \]

where \( W \) is the weight in pounds, \( H \) is the height in inches, and \( k \) is a constant of proportionality.

First, we need to determine the constant \( k \) using the information for the 132-lb person who is 66 inches tall and has a BMI of 21.3.

Given:

  • \( W = 132 \)
  • \( H = 66 \)
  • \( \text{BMI} = 21.3 \)

Plugging these values into the BMI formula, we get:

\[ 21.3 = k \cdot \frac{132}{66^2} \]

Calculating \( 66^2 \):

\[ 66^2 = 4356 \]

Thus, we can rewrite the equation as:

\[ 21.3 = k \cdot \frac{132}{4356} \]

Now, solving for \( k \):

\[ 21.3 = k \cdot \frac{132}{4356} \]

Multiplying both sides by 4356:

\[ 21.3 \cdot 4356 = k \cdot 132 \]

Calculating \( 21.3 \cdot 4356 \):

\[ 21.3 \cdot 4356 \approx 92751.48 \]

Now we can solve for \( k \):

\[ k = \frac{92751.48}{132} \approx 702.6 \]

Now that we have \( k \), we can calculate the BMI for an individual who is 61 inches tall and weighs 158 lb.

Given:

  • \( W = 158 \)
  • \( H = 61 \)

Using the BMI formula again:

\[ \text{BMI} = k \cdot \frac{W}{H^2} \]

Substituting the values of \( k \), \( W \), and \( H \):

\[ \text{BMI} = 702.6 \cdot \frac{158}{61^2} \]

Calculating \( 61^2 \):

\[ 61^2 = 3721 \]

Now substituting that in:

\[ \text{BMI} = 702.6 \cdot \frac{158}{3721} \]

Calculating \( \frac{158}{3721} \):

\[ \frac{158}{3721} \approx 0.04241 \]

Now we can find the BMI:

\[ \text{BMI} \approx 702.6 \cdot 0.04241 \approx 29.8 \]

Thus, the BMI for an individual who is 61 inches tall and weighs 158 pounds is approximately:

\[ \text{BMI} \approx 29.8 \]