The bearing of x from y is 045°and the bearing of z from y is 145°,where x,y and z are three points in the plane.lf y is equidistant from x and z,find the bearing of z from x.

Answer 1

what are the given answers?

Answer 2

From North
x is 45 deg clockwise from north
z is 145 clockwise from north so 100 clockwise from YX
so angle xyz =100
the two lengths are equal so yz=yx and
2(angles) + 100 = 180
so the other two angles are 40
z to y = 145 + 180 = 325
add 40 for z to x
365, which is 5 degrees on your compass

Answer 3

The triangle internal angle at y is 145-45=100 since the triangle is isosceles, the internal angles at x and z are both (180-100)/2=40:then the bearing of z from x is the bearing of y From x less the internal angle at x(45+180)-40=180 . therefore z from x is 185