The bearing of Q from P is 300 degrees and the bearing of R from Q is 210 degrees. If Q is equidistance from P and R, find the bearing of R from P.?

Answer 1

A man start from a point A and walks 1000m on a bearing of 025°. How far north is he from his starting point.?

Answer 2

R's bearing from P is 270-θ, where
tanθ = √2/(1+√3)

Answer 3

your 2nd question:

cos 25 = y/1000
y = 1000cos25 = ....