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The bearing of a house from point A is 319°.From a point B, 317m due east of A, the bearing of the house is 288°.

Hw far is the house from A

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If we label the house H, then in triangle ABH, angle A=131° and angle B=18°, so angle H is 180-131-18 = 31°
AH/sin18° = 319/sin31°

But please show me the diagram

i need the the diagram ugently

I need the diagram now please

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