Draw the diagram.
if the school is x meters west and y meters north of the sickbay, and z meters from the office, we have
y/x = tan30°
y/(x+317) = tan 18°
so, x tan30° = (x+317) tan18°
and, now that you have x,
(x+317)/z = cos 18°
So crank it out.
The bearing of a school from the sickbay is 310°.From the commandant's office ,317m due east of the sickbay,the bearing of the school library is 288°.How far is the library from the sickbay?
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