The Baynard High School Boosters are selling hot dogs and pretzels at the concession stand. They have 300 hot dogs and pretzels in stock and want to earn an income of $800. They plan to sell the hot dogs for $4 each and the pretzels for $2 each. How many hot dogs and how many pretzels do the boosters need to sell to reach their goal of $800?(1 point)

Question

Responses

200 hot dogs and 100 pretzels
200 hot dogs and 100 pretzels

100 hot dogs and 200 pretzels
100 hot dogs and 200 pretzels

250 hot dogs and 50 pretzels
250 hot dogs and 50 pretzels

50 hot dogs and 250 pretzels
50 hot dogs and 250 pretzels

Answer 1

To reach their goal of $800, the boosters need to sell a combination of hot dogs and pretzels that adds up to $800.

Let's assume they sell x hot dogs. Each hot dog costs $4, so the total income from selling hot dogs is 4x.

They also sell y pretzels. Each pretzel costs $2, so the total income from selling pretzels is 2y.

The total income from selling hot dogs and pretzels is then 4x + 2y.

We know that the total income needs to be $800, so we can write the equation: 4x + 2y = 800.

Now we need to find a combination of x and y that satisfies this equation and also fits within the stock of 300 hot dogs and pretzels.

Let's try option 1: 200 hot dogs and 100 pretzels.
- 200 hot dogs would bring in 4 * 200 = $800
- 100 pretzels would bring in 2 * 100 = $200
The total income would be 800 + 200 = $1000.

Since this option brings in more than the goal of $800, it is not the correct answer.

Let's try option 2: 100 hot dogs and 200 pretzels.
- 100 hot dogs would bring in 4 * 100 = $400
- 200 pretzels would bring in 2 * 200 = $400
The total income would be 400 + 400 = $800.

Since this option brings in exactly the goal of $800, it is the correct answer.

Therefore, the boosters need to sell 100 hot dogs and 200 pretzels to reach their goal of $800.