Let's say the Boosters sell x hot dogs and y pretzels.
The income from selling hot dogs would be 4x dollars.
The income from selling pretzels would be 2y dollars.
To reach their goal of $800, the equation becomes:
4x + 2y = 800.
Since they have 300 hot dogs and pretzels in stock, the equation also becomes:
x + y = 300.
We can solve this system of equations:
Multiply the second equation by 2:
2x + 2y = 600.
Subtract the second equation from the first:
(4x + 2y) - (2x + 2y) = 800 - 600,
2x = 200,
x = 100.
Plug the value of x back into the second equation:
100 + y = 300,
y = 200.
Therefore, the Boosters need to sell 100 hot dogs and 200 pretzels to reach their goal of $800. Answer: 100 hot dogs and 200 pretzels.
The Baynard High School Boosters are selling hot dogs and pretzels at the concession stand. They have 300 hot dogs and pretzels in stock and want to earn an income of $800. They plan to sell the hot dogs for $4 each and the pretzels for $2 each. How many hot dogs and how many pretzels do the boosters need to sell to reach their goal of $800?(1 point) Responses
50 hot dogs and 250 pretzels
200 hot dogs and 100 pretzels
250 hot dogs and 50 pretzels
100 hot dogs and 200 pretzels
1 answer