The Baynard High School Boosters are selling hot dogs and pretzels at the concession stand. They have 300 hot dogs and pretzels in stock and want to earn an income of $800. They plan to sell the hot dogs for $4 each and the pretzels for $2 each. How many hot dogs and how many pretzels do the boosters need to sell to reach their goal of $800?(1 point)

Question

Responses

100 hot dogs and 200 pretzels
100 hot dogs and 200 pretzels

50 hot dogs and 250 pretzels
50 hot dogs and 250 pretzels

250 hot dogs and 50 pretzels
250 hot dogs and 50 pretzels

200 hot dogs and 100 pretzels

Answer 1

To reach their goal of $800, the boosters can calculate the number of hot dogs and pretzels they need to sell using the following equations:

$4 * number of hot dogs + $2 * number of pretzels = $800

Let's solve for the unknowns. We have two variables (number of hot dogs and number of pretzels) and two equations, so we can solve the system of equations.

From the first equation, we can rewrite it as:
4H + 2P = 800

Since we know they have a total of 300 hot dogs and pretzels in stock:
H + P = 300

Now we can use substitution or elimination method to solve this system of equations. Let's use substitution.

From the second equation, we can rewrite it as:
P = 300 - H

Substitute this value into the first equation:
4H + 2(300 - H) = 800
4H + 600 - 2H = 800
2H = 200
H = 100

Now substitute the value of H into the equation we found in the second step:
P = 300 - 100
P = 200

So, the boosters need to sell 100 hot dogs and 200 pretzels to reach their goal of $800. Thus, the correct answer is:

100 hot dogs and 200 pretzels