Let h be the number of hot dogs and p be the number of pretzels. We know that h + p = 300 and 4h + 2p = 800.
From the first equation, we can solve for h: h = 300 - p.
Substituting this into the second equation, we get: 4(300-p) + 2p = 800.
Simplifying the second equation, we get: 1200 - 4p + 2p = 800.
Combining like terms, we get: -2p = -400.
Dividing both sides by -2, we get: p = 200.
Substituting this back into the first equation, we get: h + 200 = 300.
Subtracting 200 from both sides, we get: h = 100.
Thus, the Baynard High School Boosters need to sell 100 hot dogs and 200 pretzels to reach their goal of $800. Answer: 100 hot dogs and 200 pretzels.
The Baynard High School Boosters are selling hot dogs and pretzels at the concession stand. They have 300 hot dogs and pretzels in stock and want to earn an income of $800. They plan to sell the hot dogs for $4 each and the pretzels for $2 each. How many hot dogs and how many pretzels do the boosters need to sell to reach their goal of $800? (1 point)
200 hot dogs and 100 pretzels
50 hot dogs and 250 pretzels
250 hot dogs and 50 pretzels
100 hot dogs and 200 pretzels
1 answer