Let's use a system of equations to solve this problem. Let x represent the number of hot dogs sold and y represent the number of pretzels sold.
From the problem statement, we know that the boosters want to earn a total income of $800. We can express this as an equation: 4x + 2y = 800.
We also know that the boosters have 300 hot dogs and pretzels in stock. This can be expressed as a second equation: x + y = 300.
To solve this system of equations, we can use substitution or elimination.
Let's use elimination. Multiply the second equation by -2 to make the coefficients of y the same: -2(x + y) = -2(300), which simplifies to -2x - 2y = -600.
Now we can add the two equations together to eliminate the y variable: 4x + 2y + -2x - 2y = 800 + -600.
Simplifying the equation, we get: 2x = 200.
Dividing both sides by 2, we find that: x = 100.
Substituting this value back into one of the original equations, we can solve for y: 100 + y = 300.
Simplifying the equation, we get: y = 200.
Therefore, the boosters need to sell 100 hot dogs and 200 pretzels to reach their goal of $800.
The Baynard High School Boosters are selling hot dogs and pretzels at the concession stand. They have 300 hot dogs and pretzels in stock and want to earn an income of $800. They plan to sell the hot dogs for $4 each and the pretzels for $2 each. How many hot dogs and how many pretzels do the boosters need to sell to reach their goal of $800?(1 point) Responses 250 hot dogs and 50 pretzels 250 hot dogs and 50 pretzels 200 hot dogs and 100 pretzels 200 hot dogs and 100 pretzels 100 hot dogs and 200 pretzels 100 hot dogs and 200 pretzels 50 hot dogs and 250 pretzels
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