If you're trying to find the expression for the area, you have for some reason combined the x^2 and x terms (a no-no). The area is
1/2(2x^2+4x+2)(x^2+3x-4)
(x+1)^2 (x+4)(x-1)
As you say, not sure which way to go. You have an expression for the area. Was there some other objective?
The base of a triangle in terms of x is: 2^2+4x+2 and the height is x^2+3x-4
Area=1/2(2x^2+4x+2) (x^2+3x-4)= 6x^2+2 (x^2+3x-4)
Trying to find the area and not sure which direction to go
2 answers
re-evaluate your terms. I got x^4 +5x^3 -x^2 -5x-4.
my work:
.5(2x^2 +4x +2)(x^2 +3x -4)=.5(2x^4+6x^3-8x^2+4x^3+4x^2 -16x+2x^2 +6x-8)
my work:
.5(2x^2 +4x +2)(x^2 +3x -4)=.5(2x^4+6x^3-8x^2+4x^3+4x^2 -16x+2x^2 +6x-8)
4 answers