The area of the solid is a set of vertical strips of width dx.
The other edges of the triangle are the lines y = -x/2 and y=x
So the volume of the solid is
v = ∫[-12,0] (6 + x/2)^2 dx + ∫[0,6] (6-x)^2 dx = 144 + 72 = 216
The base of a certain solid is the triangle with vertices at (−12,6), (6,6), and the origin. Cross-sections perpendicular to the y-axis are squares.
2 answers
Oops. My bad. I took cross-sections perpendicular to the x-axis.
So see what you can do to fix my mistake, taking horizontal strips as the base of each square.
So see what you can do to fix my mistake, taking horizontal strips as the base of each square.