Asked by Awesomness
A solid with at most one base cannot be which of the following?
A. cone
B. cube
C. pyramid
D. sphere
Is the answer B?
A. cone
B. cube
C. pyramid
D. sphere
Is the answer B?
Answers
Answered by
Damon
A cube has 6 potential bases in my opinion.
Answered by
Awesomness
So is B the correct answer?
Answered by
Damon
I am here to help, not to feed answers.
Answered by
Damon
When I throw dice, each may land on any of the six sides.
Answered by
Awesomness
so its between a cone and a pyramid.
Answered by
Damon
NO
a cone has one base
a pyramid has one base
we need something with multiple bases
a cone has one base
a pyramid has one base
we need something with multiple bases
Answered by
Damon
If it has ONE base it CANNOT be
Answered by
Awesomness
A CUBE!!!!!!
Answered by
Damon
YES !!!!
Answered by
Awesomness
I had said a cube up at the very top. You said your not here to feed answers. All you had to say was YES!!!!!
Answered by
Damon
but I would not because I was not convinced you knew why.
Answered by
fox girl
Thx (:
Answered by
·
At most one means it can't be more than one. It would have to be a cone.
Answered by
·
I got it a bit backwards, my bad. Cube is correct.
Answered by
ash_on_lol is amazing
alr
Answered by
Kandy
I would like to add most one base cannot be Which of the following cone Cube Pyramid Sphere
Answered by
Bot
A solid with at most one base cannot be a cube. A cube has six congruent square faces, so it has six potential bases. Therefore, the correct answer is B.
Answered by
Kandy
Which of the following are considered? Sku lines AC &c D, DH and BF ,
EG and FH,EA and gh ,
EG and FH,EA and gh ,
Answered by
Bot
It seems like you are providing pairs of lines. Without further context or information, it is difficult to determine what is being considered. The lines AC and CD, DH and BF, EG and FH, and EA and GH could represent various line segments or line intersections in a geometric figure. Please provide more context or describe what these lines represent in order to answer your question accurately.