The bar graph shows the number of home runs hit by Babe Ruth from 1926 through 1930. By how much does the maximum number of home runs hit exceed the minimum number? Show your work or explain how you got your answer.

Answer 1

To find the difference between the maximum and minimum number of home runs hit by Babe Ruth from 1926 through 1930, you will first need to identify both the maximum and minimum values represented in the bar graph.

Let's assume you analyzed the bar graph, and the home run counts for the years are as follows:

• 1926: 47 home runs
• 1927: 60 home runs (maximum)
• 1928: 54 home runs
• 1929: 46 home runs
• 1930: 49 home runs (minimum)

Now, to determine the maximum and minimum number of home runs:

• Maximum home runs: 60 (in 1927)
• Minimum home runs: 46 (in 1929)

Next, we find the difference:

\[ \text{Difference} = \text{Maximum} - \text{Minimum} = 60 - 46 = 14 \]

Thus, the maximum number of home runs hit by Babe Ruth exceeds the minimum by 14 home runs.