Use the graph to answer the question.

Question

The bar graph shows the number of home runs hit by Babe Ruth from 1926 through 1930.

A vertical bar graph of home runs by Babe Ruth. The horizontal axis is for years from 1926 to 1930 in increments of one, and the vertical axis is for number of home runs numbered from 40 to 65 in increments of 5. The bar for 1926 has a height of 47, the bar for 1927 has a height of 60, the bar for 1928 has a height of 54, the bar for 1929 has a height of 46, and the bar for 1930 has a height of 48.

By how much does the maximum number of home runs hit exceed the minimum number? Show your work or explain how you got your answer.

Answer 1

To find the difference between the maximum and minimum number of home runs hit by Babe Ruth from 1926 to 1930, we first need to identify the maximum and minimum values from the heights of the bars:

• 1926: 47 home runs
• 1927: 60 home runs (this is the maximum)
• 1928: 54 home runs
• 1929: 46 home runs
• 1930: 48 home runs

From this data, the maximum number of home runs is 60 (in 1927) and the minimum number of home runs is 46 (in 1929).

To find the difference:

\[ \text{Difference} = \text{Maximum} - \text{Minimum} = 60 - 46 = 14 \]

Therefore, the maximum number of home runs hit exceeds the minimum number by 14.