The average score of all golfers for a particular course has a mean of 73 and a standard deviation of 3. Suppose

36 golfers played the course today. Find the probability that the average score of the 36 golfers exceeded 74.

1 answer

Z = (mean1 - mean2)/SEm

SEm = SD/√n

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.