The probability that the average score of the 64 golfers exceeded 61 is 0.8413. This can be calculated using the z-score formula:
z = (61 - 60) / (4 / √64)
z = 0.25
The probability of a z-score of 0.25 is 0.8413.
The average score of all golfers for a particular course has a mean of 60 and a standard deviation of 4 suppose 64 golfers played the course today find the probability that the average score of the 64 golfers exceeded 61
1 answer