To determine how many atoms of platinum (Pt) are in 195.08 grams, we can use Avogadro's number, which is approximately \(6.022 \times 10^{23}\) atoms/mol.
Since the atomic mass of platinum is 195.08 amu, this means that 1 mole of platinum weighs 195.08 grams and contains \(6.022 \times 10^{23}\) atoms.
Now, if we have 195.08 grams of platinum:
\[ \text{Number of moles of Pt} = \frac{195.08 \text{ grams}}{195.08 \text{ grams/mole}} = 1 \text{ mole} \]
To find the number of atoms, we multiply the number of moles by Avogadro's number:
\[ 1 \text{ mole} \times 6.022 \times 10^{23} \text{ atoms/mole} = 6.022 \times 10^{23} \text{ atoms} \]
Thus, the answer is:
6.022×10²³ atoms
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