The atomic mass of the element platinum (Pt) is 195.08 amu. How many atoms of platinum are in 195.08 grams?(1 point)

Responses

1.175×1026
atoms
1 point 1 7 5 times 10 to the 26th power atoms

1.951×1025
atoms
1 point 9 5 1 times 10 to the 25th power atoms

3.087×1021
atoms
3 point 0 8 7 times 10 to the 21th power atoms

6.022×1023
atoms

1 answer

To determine how many atoms of platinum (Pt) are in 195.08 grams, we can use Avogadro's number, which is approximately \(6.022 \times 10^{23}\) atoms/mol.

Since the atomic mass of platinum is 195.08 amu, this means that 1 mole of platinum weighs 195.08 grams and contains \(6.022 \times 10^{23}\) atoms.

Now, if we have 195.08 grams of platinum:

\[ \text{Number of moles of Pt} = \frac{195.08 \text{ grams}}{195.08 \text{ grams/mole}} = 1 \text{ mole} \]

To find the number of atoms, we multiply the number of moles by Avogadro's number:

\[ 1 \text{ mole} \times 6.022 \times 10^{23} \text{ atoms/mole} = 6.022 \times 10^{23} \text{ atoms} \]

Thus, the answer is:

6.022×10²³ atoms